Question

Without using trigonometrical tables, evaluate:

{ (5 cos 0° - 2 sin 30° + √3 cos 30°)/
tan 30" x tan 60° x cos 60°) }+ 3 sin 29° sec 61°​

Answer 1

try to do it alone

thanks for this

question

Answer 2

value of given trigonometric expression is 14.

we have to find the value of,

(5cos0° - 2sin30° + √3cos30°)/(tan30° × tan60° × cos60°) + 3sin29°. sec61°

we know, cos0° = 1 , sin30° = 1/2 , cos30° = √3/2

tan30° = 1/√3 , tan60° = √3, cos60° = 1/2

so, (5cos0° - 2sin30° + √3cos30°)/(tan30° × tan60° × cos60°) + 3sin29°. sec61°

= (5 × 1 - 2 × 1/2 + √3 × √3/2)/(1/√3 × √3 × 1/2) + 3sin(90° - 61°). sec61°

= (5 - 1 + 3/2)/(1/2) + 3cos61°. sec61°

= (4 + 3/2)/(1/2) + 3 cos61° × 1/cos61°

= (11/2)/(1/2) + 3

= 11 + 3

= 14