Math, asked by luckykesharwani, 1 year ago

without using trigonometry table find the value of cos70\sin20+cos57cosec33-2cos60

Answers

Answered by shivam4321

5

cos70/sin20+cos57cosec33-2cos60

= cos70/sin20 + cos57/sin33 - 2cos60

= sin20/sin20 + cos57/cos57 - 2cos60

= 1+1 - 2(1/2)

= 1

Answered by shauryagarg3001

0

cos70/sin20+cos57cosec33-2cos60

= cos70/sin20 + cos57/sin33 - 2cos60

= sin20/sin20 + cos57/cos57 - 2cos60

= 1+1 - 2(1/2)

= 1

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