without using trigonometry table find the value of cos70\sin20+cos57cosec33-2cos60
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cos70/sin20+cos57cosec33-2cos60
= cos70/sin20 + cos57/sin33 - 2cos60
= sin20/sin20 + cos57/cos57 - 2cos60
= 1+1 - 2(1/2)
= 1
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cos70/sin20+cos57cosec33-2cos60
= cos70/sin20 + cos57/sin33 - 2cos60
= sin20/sin20 + cos57/cos57 - 2cos60
= 1+1 - 2(1/2)
= 1
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