Question

Without using truth tables, show that
(i) p ∧ (q ∧ ∼p) ≡ p ∧ q
(ii) (p ∧ q) ∨ (∼p ∧ q) ∨ (∼q ∧ r) ≡ q ∨ r

Answer 1

I am not able to understand...