without using usual calculations find (11)^3-(8)^3-(3_^3
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0
Answer:
792 is the answer.
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We know that if,
a+b+c = 0
a³+b³+c³ = 3abc
Here
a = 11
b = -8
c = -3
Hence
a+b+c = 11-8-3 = 0
Therefore,
we can use the identity
a³+b³+c³ = 3abc
Hence
11³ - 8³ - 3³
= 3×11×-8×-3
= 792
Hope this is helpful to you
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