Question

withoutusing the tables find the value for:
sin60° cos 30° + cos 60° sin 30°​

Answer 1

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Given-

$sin60 = \frac{ \sqrt{3} }{2}$

$cos30 = \frac{ \sqrt{3} }{2}$

$cos60 = \frac{ {1} }{2}$

$sin30 = \frac{ {1} }{2}$

To Find-

the value of

$sin60° cos 30° + cos 60° sin 30°$

Solution-

$sin60° cos 30° + cos 60° sin 30°$

Now we substitute the value of all trigonometric ratios

So,

$=> \frac{ \sqrt{3} }{2} \times \frac{ \sqrt{3} }{2} + \frac{1}{2} \times \frac{1}{2}$

$= > \frac{3}{2} + \frac{1}{2}$

$= > \frac{4}{2}$

$= > 2$

Answer 2

Step-by-step explanation:

30°and 60°

are angles of one of the standard triangles

sin(30°)=1/2

cos(30°)=√3/2

sin(60°)=√3/2

cos(60°)=1/2

So

sin(60°)•cos(30°)+sin(30°)•cos(60°)

=(√3/2)(√3/2)+(1/2)(1/2)

=3/2+1/2=4/2=2