witout adding find 1+3+5+7+9+11+13+15+17+19
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the sets of no. are in AP
a=1 d=2 n=10
Sn=n/2(2a+(n-1)d)
so S10=10/2(2×1 +(10-1)2)
therefore S10=100
hence the sum is 100
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