Question

wjat is the sign of delta s for following reactions caco3→cao→co2

Answer 1

Answer:

delta s is positive

Explanation:

A gas in on the product side but but only solid on the reactant side.Hence there is an increase in entropy, and delta s is positive

the correct reaction is:

CaCO3(s)------->CaO(s)+CO2(g)

Answer 2

The sign of ∆S is positive.

• Negative entropy or lowering entropy means a decrease in the number of moles on the product side.
• Positive entropy or increasing entropy means an increase in the number of moles on the product side.
• The given reaction is $CaCO_3\rightarrow CaO+CO_2$.
• There is an increase in the number of moles on the product side so, entropy increases and ∆S is positive.