wo blocks A and B of mass mA and mB , respectively, are kept in contact on a frictionless table. The experimenter pushes block A from behind, so that the blocks accelerate. If block A exerts force F on block B, what is the force exerted by the experimenter on block A?
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Answer:
∴ Force exerted by the experimenter on block A is F[1+mA/mB]
Explanation:
Let F’ = force exerted by the experimenter on block A and F be the force exerted by block A on block B.
Let a be the acceleration produced in the system.
For block A,
F’-F=mAa …(1)
For block B,
F = mBa …(2)
Dividing equation (1) by (2), we get:
F’/F-1=mA/mB
⇒F’=F[1+mA/mB]
∴ Force exerted by the experimenter on block A is F[1+mA/mB]
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Let F’ = force exerted by the experimenter on block A and F be the force exerted by block A on block B.
Let a be the acceleration produced in the system.
For block A,
F’-F=mAa …(1)
For block B,
F = mBa …(2)
Dividing equation (1) by (2), we get:
F’/F-1=mA/mB
⇒F’=F[1+mA/mB]
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