Question

wo
(Given)
2 PBA = 2 PCA = 90° (Given)
PA = PA
(Common)
A PAB EA PAC
(RHS rule)
Z PAB = L PAC
(CPCT)
te that this result is the converse of the result prove
=
EXERCISE 7.3
1. A ABC and A DBC are two isosceles triangles on
the same base BC and vertices A and D are on the
same side of BC (see Fig. 7.39). If AD is extended
to intersect BC at P, show that
(i) A ABD=AACD
(ii) ΔΑΒΡΔΑCP
(iii) AP bisects Z A as well as Z D.
(iv) AP is the perpendicular bisector of BC.​

Answer 1

ANSWER: (iv) AP is the perpendicular bisector BC