Question

wo lead spheres each of mass500g are kept centers 1m apart.find the gravitational force with wich they attract each other

Answer 1

Answer:

$1.66825 \times {10}^{ - 11} newton$

Explanation:

ACCORDING TO UNIVERSAL LAW OF GRAVITATION:

FORCE OF ATTRACTION BETWEEN TWO BODIES = G (Mm)

d^2

KEYWORDS:

M= Mass of first body

m=mass of second body

G=Universal gravitational constant

d=distance between the objects.

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FOR THIS CASE:

M= 500g=0.5kg

m=500g=0.5kg

G=

$6.673 \times {10}^{ - 11} n {m}^{2} \div {kg}^{2}$

d=1 metre

F=FORCE OF ATTRACTION BETWEEN BODIES=?

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NOW FORCE OF ATTRACTION BETWEEN THESE SPHERICAL BODIES=

F= G(Mm)

d^2

F=

$6.673 \times {10}^{ - 11} \times 0.5kg \times 0.5kg \div {1}^{2}$

$= 6.673 \times {10}^{ - 11} \: \: \times \: \: 0.25$

$f = 1.66825 \times {10}^{ -} 11newton$

THEREFORE FORCE OF ATTRACTION BETWEEN THESE TWO SPHERES IS

$1.66825 \times {10}^{ - 11} newton$

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BY SCIVIBHANSHU

THANK YOU

STAY CURIOUS.