Question

wo prizes are to be given among ten persons.) If both the prizes
are not to be given to one person. (ii) If both the prizes can be given
to one person, find the number of ways in which the prizes can
be given.​

Answer 1

Answer:

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Step-by-step explanation:

A prize can be given to any of the 10 boys. So for each prize there are 10 options.

So total number of ways possible to distribute the 2 prizes are = 10^2 = 100

Now from these total cases we need to substract the cases where the prizes go to same person.

This can happen in 10ways ie all prizes gone to boy1boy2,boy3,boy4,boy5 ,boy 6,boy 7,boy 8,boy 9,boy 10.

So required cases = 100 - 10 =90