Question

wo transparent slabs having equal thickness but different refractive indices µ1 and µ2 are pasted side by side to form a composite slab. This slab is placed just after the double slit in a Young’s experiment so that the light from one slit goes through one material and the light from the other slit goes through the other material. What should be the minimum thickness of the slab so that there is a minimum at the point P0 which is equidistant from the slits?

Answer 1

Answer:

minimum at point P0 is  λ2μ1-μ2.

Explanation:

Given:

Refractive index of the two slabs are µ1 and µ2.

Thickness of both the plates is t.

When both the strips are fitted, the optical path changes by

∆x=(μ1-1 )t-( μ2-1 )t      =(μ1-μ2 )t

For minimum at P0, the path difference should be  λ2.

i.e. ∆x=λ2

λ2=(μ1-μ2)t⇒t=λ2μ1-μ2

Therefore, minimum at point P0 is  λ2μ1-μ2.

Answer 2

Answer:

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