Question

woman is now 30 years older than her son .15 years ago she was twice as old as her son .find the present age of the woman and her son. solve in one variable

Answer 1

Let the woman's Present age be X
Then son's present age will be ( X- 30)

15 years ago
Woman was ( X - 15)
Son was (X-30) - 15 = X-45

But
ACQ
W = 2 (S)........ (15 years ago situation)

(X-15) = 2 (X-45)

X-15 = 2X - 90

X - 2X = - 90 + 15

- X = - 75

Multiplying both sides by (-)

X = 75

So the present ages are
Woman = 75 years
Son = 75 - 30 = 45 years

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Answer 2

Answer:

ans:75,45

Step-by-step explanation:

women age :x

sons age : x-30