Question

Woman is q years old while her son is p year old.the sum of their ages is equal to twice the difference of their ages .the product of their ages is 675.write down the equation connecting their agesand solve the equation in order to find the ages of the woman and her son

Answer 1

Answer:

675=xp or x into p

=675/2

Answer 2

Answer:

A woman is Q years old while her son is P years old.

The sum of their ages is equal to twice the difference of their ages.

Q + P = 2(Q - P))

Q + P = 2Q - 2P

P + 2P = 2Q - Q

3P = Q

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The product of their ages is 675.

Q * P = 675

Replace P with 3P

3P * P = 675

3P^2 = 675

Divide by 3

P^2 = 225

P = sqrt%28225%29

P = 15 yrs is the son

and obviously

3(15) = 45 yrs is woman

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You can confirm this in both statements