Question

woodem slab starting from rest . slides down o inclined plane of length 10m with an acceleration of 5ms-2. what would be its speed at the bottom of its speed at the bottom of the inclined plane?

Answer 1

Hello friend

Wooden slab starts sliding down from rest

So the initial velocity u=0

The length of the inclined plane is 10 m

So s=10

Its acceleration is 5m/s²

So a=5m/s²

We need to find the final velocity i.e v

Using the equations of motion

v²-u²=2as

v²-0²=2*5*10

v²=100

v=√100

So v is 10

The final velocity of the Wooden slab is 10m/s

Answer 2

Concept Introduction:-

It is a type branch of mathematics which deals with the properties and

also manipulation of numbers.

Given:-

We have been given some length.

To Find:-

We have to find inclined plane.

Solution:-

According to the problem

Wooden slab starts sliding down from rest

So the initial velocity u=0

The length of the inclined plane is 10 m

So s=10

Its acceleration is 5m/s²

So a=5m/s²

We need to find the final velocity is v

Using the equations of motion

v²-u²=2as

v²-0²=2*5*10

v²=100

v=√100

So v is 10

The final velocity of the Wooden slab is 10m/s

Final Answer:-

The final answer is 10m/s

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