Question

Wooden toy is in the form of a cone surmounted on a hemisphere with diameter of the base of the cone is 6 cm and its height is 4 cm find the cost of painting the toy at the rate of 5 rupees per 1000 CM square

Answer 1

Answer:

.TSA of the Toy

πrl +2πr^2, r is radius=3cm, h=4cm

l=slant height of Cone,l=v3^2+4^2 = 5cm

πrl+2πr^2 = πx3x5+ 2πx3x3

I5π+18π = 33π = 33x3.14=103.62cm2

cost of painting = lO3.62x5/1000=.

52ps

Answer 2

Answer:

33π/200

Step-by-step explanation:

surface area of inner part of toy

i.e. surface area of hemisphere = 2Πr^2

= 18π

now,

surface area of cone = πr( √(h^2 + r^2) )

= 15π

15π+ 18π = 33π

it costs 5 RS per 1000 cm square

thus 1/200 RS per cm square

now ,

answer would be

33π/200