Word Problems:- 1. An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach -350 m deep from the ground? 2. The temperature of town A at 4 p.m. was 41°C above zero. The temperature recorded at 10 p.m. was 29°C. If the temperature falls at a constant rate per hour, find the fall in temperature per hour.
Answers
Answer:
1) 1 hour
2) 2 hour
Step-by-step explanation:
1) Given :-
Initial height = 10m
Final depth = 350m
Note :- Distance descended in denoted by a '-ve' integer.
Now :-
Distance to be descended :
=> x = (-350) - (10)
=> x = -350 - 10
=> x = -360m
So,
Total distance to be descended by the elevator is -360m.
Thus,
To descend -360m, time taken by elevator is :
=> x = -360/-6
=> x = 60
We know that :-
60 minutes = 1 hour
Therefore answer = 1 hour
2) Ans :-
=> The fall in temperature is 2° per hour.
=> Time taken fall in temperature is 10 - 4 = 6
=> Temperature fall in 6 hours = 41 - 29
= 12
=> Fall in temperature hour = 12/6 = 2 hour Ans.
Answer:
The elevator descending for 1 minute =6m
it descending 10 m above ground level
it reached -350m below ground level
the time taken to reach -350m below the ground level 350+10m
Step-by-step explanation:
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