Question

Word problems

1) The area of a rectangle is 6x²+17xy+12y². If its length is 3x+4y, find its width. Hence, find its perimeter.​

Answer 1

Step-by-step explanation:

It is given that

Area of a rectangle  6x^2−4xy−10y2 square unit

Length = 2x+2y unit

We know that

Breadth = $\red \bigstar{ \sf { \dfrac{Area }{ Length}}}$

So we get

=(6x2−4xy−10y2)/(2x+2y)

3x−5y units