work done by 1kg of water when it falls through the height of 1000cm is
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Work done=Fs
=mas=1×9.8×10m=98J
{F=ma}
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Given:
Mass of Water= 1kg
Height from which water Fallen= 1000cm
To Find:
Work done by water while falling
Solution:
We know that,
⟼ 1000cm= 10m
⟼ Force= Mass×Acceleration
⟼ Work= Force×Displacement
Here,
Displacement(d) is 10m
Acceleration due to gravity is 9.8m/s²
So,
↬ F= ma
↬ F= 1×9.8= 9.8N
↬ Work done= F×d
↬ Work done= 9.8×10
↬ Work done= 98J
Hence, the work done by the water is 98J.
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