Work done by a force=(3i+2j)n in displacing a particle from (1m,1m)to(2m,2m) is
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Answer:
w= 5J
Explanation:
work done =force . displacement cos theta
force = 3i+ 2j
displacement = 2-1,2-1( that is displacement some what equal to 1)
= 1i+ 1j
therefore by doing dot product
work done is
= 3×1+2×1
=3+2
w =5 J
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