Question

Work done by a force F = yi + xj as the particle is
taken from (1, 2) to (3, 4) is​

Answer 1

Answer:

Work was done ∫Fdt

When particle moves from 0 to a along x-axis

Then W1=∫0a−(Kyi)dx=0         ∵y=0

Now, when the particle moves parallel to the y-axis

W2=∫0a−(Kaj)dy         ∵x=a

∴W2=−Ka∫0ady=−Ka2

∴W=W1+W2=−Ka2

Explanation:

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