Question

Work done by air whem it expands from 500 litres to 150 litres at a constant pressure of 2 atmosphere​

Answer 1

∆W = P ∆V

∆W = 2 × 10^5 (150 - 500) × 10^(-3)

∆W = -70 kJ

Answer 2

Question

Work done by air whem it expands from 500 litres to 150 litres at a constant pressure of 2 atmosphere

Solution

Given :

• Atmospheric Pressure,P = 2 atm

• Initial Volume, $\sf V_1$ = 500 L

• Final Volume,$\sf V_2$ = 150 L

To finD

Work Done during expansion

$\rule{300}{2}$

Work Done by a gas during a thermodynamic process is given as :

$\huge{\boxed{\boxed{\sf{W = P \Delta{V}}}}}$

Change In Volume

$\sf \Delta{V} = V_2 - V_1 \\ \\ \leadsto \sf \Delta{V} = - 350 L \\ \\ \leadsto \sf \Delta{V} = - 350 \times 10^3 m^{- 3}$

$\rule{300}{2}$

Putting the values,we get :

$\sf W = 2 \times 10^5 \times - 350 \times 10^{-3} \\ \\ \longrightarrow \sf W = - 7 \times 10^3 J$