Physics, asked by fs9u7vpdjb, 9 months ago

Work done by (in first 2 seconds of motion) 1. Weight 2. Friction 3. Normal reaction

Answers

Answered by jaiusankar
0

Explanation:

  1. work done (weight) = mg.s

= ma.g.s

= m(v-u)/2.s

work done (weight) = mgs(v-u)/2

2. w.d ( friction ) = uN .s (if the object is in rest )

= u.m(v-u)/2.s

= mus(v-u)/2

3. w.d (normal) = w.d ( weight ) if the object is In rest :););):);)

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