Physics, asked by kavi3978, 1 year ago

Work done during an infinitesimal quasi-static reversible thermodynamic process is

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Answered by Anonymous
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In a quasistatic process, the difference between the external pressure and the internal pressure is infinitesimal for each infinitesimal change in the volume of the system.
Pext=Pint±dP

As you know that the term for work in terms of pressure is given by,
dW=PdV.

This means that work obtained will be maximum if the pressure is maximum for each infinitesimal change in volume.

In a reversible process, the work done in each step obtained is maximum since the external pressure in only infinitesimally greater (or smaller) than the internal pressure.
This enables us to connect the internal pressure and external pressure using the ideal gas law, which in turn enables us to derive work in terms of volume change, without knowing the pressure.
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