Chemistry, asked by hindilearn6659, 1 year ago

Work done during expansion of a gas from volume 4dm3 to 6dm3 against a constant external presure of 3 atm is

Answers

Answered by nosumittiwari3
10
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answer=> Work of expansion = - P∆V 

= -3*(6-4) = 6 lit atm = -600J


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