Physics, asked by averypeter, 4 months ago

Work done during expansion of a gas in an isobaric process due to heating from
temperature T1 to T2 is
(A) R (T1-T2) (B) R (V1-V2) (C) Cp-Cv
(D) Cp/Cv​

Answers

Answered by farhaanaarif84
1

Answer:

Work done in an adiabatic expansion is given by

W=

γ−1

R

[T

1

−T

2

].(i)

where, T

1

= initial temperature of the gas

T

2

= final temperature of the gas

γ= adiabatic constant

R= universal gas constant

Now, universal gas constant is given by:

R=C

p

−C

v

Hence, equation (i) becomes

W=

γ−1

C

p

−C

v

[T

1

−T

2

]

Because, γ=

C

v

C

p

, so we have

W=

C

v

C

p

−1

C

p

−C

v

[T

1

−T

2

]

W=

C

v

C

p

−C

v

C

p

−C

v

[T

1

−T

2

]

or W=C

v

(T

1

−T

2

).

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