Work done during isothermal expansion. Of one of an ideal gas from 10atm to 1 atm at300 k is
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using the formula
w=2.0303nrtlogp2/P1
therefore:
w=2.303*1*8.314*1
here n =1
and log 10=1
solve it you will get the answer
w=2.0303nrtlogp2/P1
therefore:
w=2.303*1*8.314*1
here n =1
and log 10=1
solve it you will get the answer
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