Question

work done in a 50 kg block through a horizontal distance of 10 m by applying a force of 100N which makes an angle of 60° with the horizontal is?​

Answer 1

Answer:500joule

Explanation:here u have only to take horizontal component in consideration....as workdone by vertical component of force is 0 hence 100 costheta which is 1/2 hence 50*10 which is equal to 500 joule hence friction is absent there is no use of mass