Question

work done in a turning magnet of magnetic dipole moment M by 90degree from stable equilibrium 4cm position in n time the corresponding work done in a turn it through an angle of 60degree find the value of n and what is work of 4cm position ​

Answer 1

Answer:

n=2

Explanation:

W=MB(cos0−cos90)=MB

W1=MB(cos0−cos60)=0.5MB

n=2