Chemistry, asked by jaikumar5751, 1 year ago

Work done in an adiabatic gas change only depends upon

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Answered by butterflyqueen
2
!! Hey mate !!

 PVγ = K (Constant)               (14)
Where γ is the ratio of specific heat (ordinary or molar) at constant pressure and at constant voluume
     γ = Cp/Cv
Suppose in an adiabatic process pressure and volume of a sample of gas changs from (P1, V1) to (P2, V2) then we have
     P1(V1)γ=P2(V2)γ=K 
Thus, P = K/Vγ
Work done by gas in this process is
     W = ∫PdV
where limits of integration goes from V1 to V2
Putting for P=K/Vγ, and integrating we get,
     W = (P1V1-P2V2)/(γ-1)          (16)
In and adiabatic process if W>0 i.e., work is done by the gas then T2< T1
If work is done on the gas (W<0) then T2 > T1 i.e., temperature of gas rises.

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