Question

Work done in an open vessel at 300k, when 56g iron reacts with dilute HCL.

Answer 1

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We know that Molar mass of Fe = 56 and R = 2 cal^-1 K mol^-1

W = P(nRT/P) n = 56/56 = 1

= 1 * 2 * 300

= 600 calorie.

Hope this helps!

Answer 2

Answer:

We know that Molar mass of Fe = 56 and R = 2 cal^-1 k mol^-1

W=p(nRT/P) n = 56/56 =1

= 1*2*300

= 600 calorie.

Hope it helps

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