Question

Work done in increasing the size of a soap bubble from a radius of 3 cm to 5 cm is nearly: (Surface tension of soap solution = 0.03 Nm^-1)
(1) 4 π mJ
(2) 0.2 π mJ
(3) 2π mJ
(4) 0.4π mJ​

Answer 1

Answer:Soap bubble has 2 surfaces ,, work done to increased size of a soap bubble =surface tension×2×change in area

Explanation:

Work done=0.03×2×(4πR1*2_4πR2*2)

=0.03×2×4π(5*2-3*2)×10*-2)

=384×10*-4×π

=App=0.4πmilli joules I hope you understand well thank you