work done in joules when two moles of ideal gas are compressed at 300 K from 1dm3 to 100dm3 against constant pressure of 3.2×105NM-2
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Answer:
n=2 moles
V
1
=5m
3
V
2
=1dm
3
=10
−2
m
3
T
1
=300K
P=100KP
a
=10
5
P
a
work done =−PΔV
=−10
5
(V
2
−V
1
)
=−10
5
(10
−2
−5)
work done =−499KJ
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