Physics, asked by deepika411799, 1 month ago

Work done in lifting a stone of mass
1kg through a height of 2m in water whose a
specific gravity is 1.25 is
(g = 10m/s)
J​

Answers

Answered by madhhahsus262
0

Answer:

relative density is the ratio of density of object to the density of medium. Here medium is water.

RD=

density of water

density of stone

=2

Stone is Two times denser than water.

According to Archimedes principle of floatation, it will sink at the bottom.

But its Apparent weight inside water will be = Actual weight - Buoyant force

-

Actual weight = volume of stone x density of stone x g = mg

Buoyant force = Weight of water displaced by the stone = volume of stone x density of water x g

density of water =

2

density of stone

So buoyant force = volume of stone x (

2

1

density of stone) x g =

2

1

× actual weight of stone =

2

mg

Therefore apparent weight of stone in water =mg−

2

mg

=

2

mg

---

Work done to raise it throught height h = apparent weight x h

W=

2

mgh

=

2

6×10×(4−1)

=90 J

Explanation:

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