Work done in lifting a stone of mass
1kg through a height of 2m in water whose a
specific gravity is 1.25 is
(g = 10m/s)
J
Answers
Answer:
relative density is the ratio of density of object to the density of medium. Here medium is water.
RD=
density of water
density of stone
=2
Stone is Two times denser than water.
According to Archimedes principle of floatation, it will sink at the bottom.
But its Apparent weight inside water will be = Actual weight - Buoyant force
-
Actual weight = volume of stone x density of stone x g = mg
Buoyant force = Weight of water displaced by the stone = volume of stone x density of water x g
density of water =
2
density of stone
So buoyant force = volume of stone x (
2
1
density of stone) x g =
2
1
× actual weight of stone =
2
mg
Therefore apparent weight of stone in water =mg−
2
mg
=
2
mg
---
Work done to raise it throught height h = apparent weight x h
W=
2
mgh
=
2
6×10×(4−1)
=90 J
Explanation:
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