Question

work done in moving 5 coulomb charges from A to B is 75 joule if potential at a is 25 volt find potential at b

Answer 1

Given conditions ⇒

Charge(Q) = 5 C.
Work done in bringing the Charge from Point A to B(W) = 75 J.

Potential at Point A (V₁) = 25 V.
Potential at Point B = V₂. 

Now, Using the Formula, 

V₂ - V₁ = W/Q

⇒ V₂ - 25 = 75/5
V₂ = 15 + 25
V₂ = 40 V.


Hence, the Potential at Point B is 40 V.


Hope it helps.

Answer 2

Final Answer : $V_{b} = 40 \: V$

Steps :
1) We have,
Work done in moving a charge from A to B = 75 J
$V_{a} = 25 \: V$
charge, q = 5 C

We know that,
$W_{ext \: A -\ \textgreater \ B } = q \: ( V_{b} - V_{a} ) \\ =\ \textgreater \ 75. = 5 ( V_{b} - 25) \\ =\ \textgreater \ 15. = V_{b} - 25 \\ =\ \textgreater \ V_{b} = 40 \: V$


Hence, Potential at point B is 40 V