Question

Work done in moving 5c charge across the ends of a conductor is 100j.If the potential at one end of conductor is 10v.Find the potential at the other end of this conductor. plzz answer it correctly .... or i will report...

Answer 1

Answer:

Explanation:

Solution,

Here, We have

Charge, Q = 5 C

Work Done, W = 100 J

Potential difference, V₁ = 10 V.

To Find,

Potential difference the at other end, V₂ = ?

Here,

Let V₂ be the Voltage at the other end of the Conductor.

Now, We know that,

Work Done = Potential Difference/Charge

W = V/Q

So, putting all the values, we get

W = V/Q

⇒ W = (V₂ - V₁)/Q

⇒ 100 = (V₂ - 10)/5

⇒ 500 = V₂ - 10

⇒ 500 - 10 = V₂

⇒ V₂ = 490 V.

Hence, the potential at the other end of the Conductor is 490 V.

Answer 2

Answer:

Workdone by charge = q. Δv [given the charge is positive]

100 = 5 (V1 - V2) [ since, workdone is positive, it means Δv is also positive]

100/5 = V1 - V2

20 = V1 - V2

V1 = 20 + V2

= 20 + 10 = 30 V

Explanation:

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