Question

work done in moving a 50 kg block through a horizontal distance of 10 metre by applying a force of hundred Newton which makes an angle of 60 degree with the horizontal is

Answer 1

as given in your answer m=50kg
s=10m
angle =60degrees
F=100N
so we know that formula
W=F.Scos thaya
so cos60= 1/2
then W= 100.10.1/2
that =500
so your answer is 500joule

Answer 2

Heya........!!!!!

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Given to us in the question :-

• Mass of block = 50 Kg
• Distance (d) = 10 m
• Force applied ( F ) = 100 N
• Angle between force and distance( α)= 60°

We know that Work done ( W ) is = F × d × cosα

Substituting the values in the formulae we get :-

=> W = 100 × 10 × cos60°

*( cos60° = 1/2 )

=> W = 100 × 10 × 1/2
=> W = 100 × 5

=> Work done = 500 J


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