Question

Work done in moving a charge of
2 C from a point at 118 V to a point at
128 V is​

Answer 1

$\underline{ \boxed{ \bold{ \mathfrak{ \huge{ \purple{Answer}}}}}}$

Given :

A charge of 2C moving from a point at 118V to a point at 128V

To Find :

Work done in moving a charge...

Formula :

$\dagger \: \: \underline{ \bold{ \rm{ \pink{W = q \triangle{V}}}}} \: \: \dagger \\ \\ \rm \: here \: \triangle{V} = 128 - 118 = 10 \: volt$

Calculation :

W = 2 × 10

$\underline{ \boxed{ \orange{ \bold{ \huge{ w = 20 \: J}}}}} \: \red{ \star}$

Answer 2

$\huge \fcolorbox{red}{pink}{Solution :)}$

Given ,

Charge = 2 C

Potential difference = (128 - 118) volt i.e 10 v

We know that , work done to move a unit charge is called potential difference

So ,

$\sf \large \fbox{Potential \: difference = \frac{work \: done }{charge} }$

Substitute the known values , we get

Work done = 10 × 2

Work done = 20 joule

Hence , 20 joule is the required answer

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