work done in stretching a spring of spring constant 100 N/m through a length of 10cm
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Answered by
14
W= fd
W= (100N) * (10m)
W= 1000J
noormahammad20pe61d9:
U=1/2Kx^2
1/2×100×-100=1/2
Answered by
15
Answer:
the answer is 50×10³J
Explanation:
here spring constant(k)=100N/m
x=10cm , d=10cm
we know the formula for potential energy is.
U=1/2kx²=1/2×100×10²=50×10²
50×10² is considered as the force
we know the formula for work done
W=F.S
W=50×10²×10
=50×10³
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