Question

work done of heating one mol of ideal gas at constant pressure from 15 to 25



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Answer 1

Answer:

Work done, W = P δV

⇒W=nRδT

⇒W=1×8.314×(25−15)

⇒W=8.314×10=83.14J

⇒W=83.14×0.24cal

Therefore, W = 19.87 cal .

Answer 2

Answer:

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