Physics, asked by dhruv777777777, 7 months ago

Work done to rotate the dipol 180 from 90

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Answered by syedaamaturraheem
0

Answer:

Therefore we have that the work done by the external field in rotating the electric dipole through some angle is W=∫θfθiqEsinθrdθ+∫θfθiqEsinθrdθ. Therefore W=2∫θfθiqrEsinθdθ. where the electric dipole is given by →p=q→ℓ and has magnitude p=qℓ.

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