Question

Work done to stretch an ideal spring from its natural length by 1mm is 10J. The amount of work required to stretch the spring by 1mm in joules is_____​

Answer 1

Explanation:

ANSWER

Force constant,

k=

x

F

=

0.001

10

=10

4

N/m

Work done =

2

1

kx

2

=

2

1

×10

4

×(

1000

40

)

2

=

2

1

×10

4

×

10

4

16

=8 J

Answer 2

Answer:

so here's the answer refer the picture

Explanation:

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