Question

Work done when a force f=(i+2j+3k) n acting on a particle

Answer 1

Answer:

what's your question?????

Answer 2

Answer:

The work done is 34 J.

Explanation:

Given that,

Force $F=(i+2j+3k)\ N$

Suppose if the particle is displaced from the point with the position vector (2i+2j+2k) to the point with the position vector (3i+4j+5k).

If $OA =2i+2j+2k$

$OB=3i+4j+5k$

We need to calculate the displacement

$d= OB-OA$

Put the value into the formula

$d=3i+4j+5k-2i+2j+2k$

$d=i+6j+7k$

We need to calculate the work done

Using formula of work done

$W=F\cdot d$

Put the value into the formula

$W=i+2j+3k\cdot (i+6j+7k)$

$W=1+12+21$

$W=34\ J$

Hence, The work done is 34 J.