Question

work efficiency of anuja is three times that of babita and anuja is able to complete a piece of work in 120 days in how many days can they together complete the work?​

Answer 1

Step-by-step explanation:

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Answer 2

Given:

The ratio of efficiency of Anuja to Babita = 3:1

Time required by Anuja to complete one work = 120 days

To find:

Total days to complete one work together.

Solution:

The ratio of work efficiency of Anuja to Babita = 3: 1

Let us take work done by each of them to be 'x'

Work efficiency becomes = 3x : x

Since, time is the reciprocal of efficiency,

A: B = 1/3x : 1/x

As, time required by Anuja = 120 days

Hence, 1/3x = 120

x = 1/ (3 × 120)

Total time required by Anuja and Babita = $\frac{1}{3x}$ + $\frac{1}{x}$

= $\frac{1}{120}$ + $\frac{1}{3 * 120}$

Total time required by Anuja and Babita to complete the work = 90 days