work function of a metal is 6.63×10^-19 find the threshold frequency of it
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Using the Formula
E= hf.
Where E is the work function, h is the plank's constant, f being the threshold frequency.
f= (6.63x10^-19)/(6.63x10^-34)
=1x10^15.
f= 1x 10^15 or 1 PHz(Peta Hertz)
E= hf.
Where E is the work function, h is the plank's constant, f being the threshold frequency.
f= (6.63x10^-19)/(6.63x10^-34)
=1x10^15.
f= 1x 10^15 or 1 PHz(Peta Hertz)
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