Physics, asked by shrestha7816, 6 months ago

Work function of Caesium is 2.14eV. If it's stopping potential is 0.60V , find the wavelength of the incident radiation

Answers

Answered by AbhaySachan

2

Explanation:

b) Wavelength of incident photon =

hc/ev + W

By substituting the values we get

Wavelength = 4.5×10^ -7 m

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