Work function of potassium is 2.2 eV. What is the threshold frequency of photoelectron?
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Answered by
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Photoelectric effect takes place when energy of the incident photon is greater than work function of the metal.
Energy of incident photon E=
λ( in A
o
)
12400
eV
(a) : Energy of photon E=
5650
12400
=2.2eV
So, potassium will not show photoelectric effect whereas cesium will show.
(b) : Energy of photon E=
5180
12400
=2.4eV
So, both will show photoelectric effect.
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