Work function of the metal is 4ev.to. to eject the photo electrons with zero velocity the wave length of the incident light should be
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The work function for a metal is 4eV.To emit a photon-electron of zero velocity from the surface of the metal,the wavelength of incident light should be
(a)2700A∘(b)1700A∘(c)5900A∘(d)3100A∘
A)
hV=work function +K.E
Given K.E=0
hV=4eV
4=12375λ
(where λ is in A∘)
∴λ=3100A∘
Hence (d) is the correct answer.
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