Work it out please...
Find the first, fourth, and the tenth terms of the arithmetic sequence described by the given rule: A(n)=12 + (n-1)(3)
A. 12,24,42
B. 0,9,27
C. 3,24,27
D. 12,21,39
Answers
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Answered by
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Step-by-step explanation:
Given: An arithmetic sequence with rule
A
n
=
12
+
(
n
−
1
)
(
3
)
Arithmetic sequences have a general rule:
A
n
=
A
1
+
(
n
−
1
)
d
where
d
= common difference between consecutive terms.
A
1
=
12
+
(
1
−
1
)
(
3
)
=
12
+
0
=
12
A
4
=
12
+
(
4
−
1
)
(
3
)
=
12
+
3
(
3
)
=
21
A
10
=
12
+
(
10
−
1
)
(
3
)
=
12
+
27
=
39
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