Math, asked by abudi1998, 2 months ago

Work out

1. Five is added to a number and the result is multiplied by five the product is 5. Find the original number

2. The elder brother is 6 years older than the younger brother. The sum of their ages is 26. Find the age of the younger and older brother respectively.

3. Three over two of a number is one tenth then what is a number?

4. Show that 2x-6 > 4 and 2x - 8>2 are equivalent

5. Solve for x 8x - 0.00932 = 7x + 0.00843

6.2 1/2 mts, 120cm

a. Calculate the ratio of the first number to the second
b. calculate the ratios of the second number to the second​

Answers

Answered by Anonymous
5

Answer:

here is ur answer mate::::

Let Rohit's age be x years.

Since, Ritu is 5 years younger than her brother Rohit, her age =x−5

Given, father is 25 years older than Ritu => Father's age =x−5+25=x+20

Four years ago, Rohit's age =x−4, Ritu's age =x−9, Father's age =x+16

Given, four years ago, the fathers age was twice the sum of the ages of Rohit and Ritu

=>x+16=2(x−4+x−9)

=>x+16=4x−26

=>3x=42

x=14

Hence, Rohit's age =14 years

Ritu's age =x−5=9 years

Father's age =x+20=34  years

hope it helps..

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